b^2+3(b-1)=b^2+5

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Solution for b^2+3(b-1)=b^2+5 equation: 



b^2+3(b-1)=b^2+5

We move all terms to the left:

b^2+3(b-1)-(b^2+5)=0

We multiply parentheses

b^2+3b-(b^2+5)-3=0

We get rid of parentheses

b^2-b^2+3b-5-3=0

We add all the numbers together, and all the variables

3b-8=0

We move all terms containing b to the left, all other terms to the right

3b=8

b=8/3

b=2+2/3

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